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JEE Class main Answered

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Asked by Patel | 06 Aug, 2021, 10:20: PM
answered-by-expert Expert Answer
Given: f(x) = tan x - tan 2x
f'(x) = sec2x - sec22x (2)
f'(x) = sec2x - 2 sec22x
Take f'(x) = 0
sec2x = 2 sec22x
Which is not possible.
Thus, f has no critical point
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