We know power, P = V²/R

 

thus R = V²/P

for both the devices the reistances will be:

R1 = 1100 ohm

and R2 = 4400 ohm

 

total resistance of series combination: R = R1+R2 = 5500 ohm

when it is connected across 440V the current flowing will be: I = 440/5500 = 4/50 = 2/25 A

now the power frlowing through the devices will be given by I²R

P1 = I²R1

and P2 = I²R2

 

the device with power exceeding the power rating will burn out.