CBSE Class 9 Answered
Asked by kishor.kp14 | 19 Jun, 2019, 09:49: AM
Expert Answer
When f(x) = x2 + ax2 + bx + 6 is divided by (x - 3) leaves a remainder 3.
→ f(3) = 3 ... By remainder theorem
→ (3)2 + a(3)2 + b(3) + 6 = 3
→ 9 + 9a + 3b + 6 = 3
→ 9a + 3b + 15 = 3
→ 9a + 3b = -12
Dividing both the sides by 3, we get
→ 3a + b = -4 .... (i)
(x - 2) is a factor of f(x)... given
→ x = 2
f(2) = 0 ..... By factor theorem
→x2 + ax2 + bx + 6 = 0
→(2)2 + a(2)2 + b(2) + 6 = 0
→ 4 + 4a + 2b + 6 = 0
→ 4a + 2b = -10
Dividing both the sides by 3, we get
→ 2a + b = -5 ... (ii)
Subtracting (ii) from (i), we get
a = 1
Put a = 1 in (ii), we get
2(1) + b = -5
→ b = -7
Answered by Yasmeen Khan | 19 Jun, 2019, 10:15: AM
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