CBSE Class 12-science Answered
Asked by Praveen Kumar | 02 May, 2014, 08:26: PM
Expert Answer
1/s+p +1/s+p =1/r
r(s+p+s+q)=(s+p)(s+q)
r(s+p+s+q)=s2+sp+sq+pq
s2+s(p+q-2r)+pq-pr-qr=0
acoording to the given condition that both roots are of equal in maginitute and opposite in sign, then
sum of roots = 0
p+q-2r=0
p+q=2r ... (i)
Now,
the product of roots=pq-pr-qr
=pq-r(p+q)
= pq-2r2 [From (i)]
Answered by Avinash Soni | 04 May, 2014, 07:42: AM
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