Asked by
| 5th Dec, 2012,
07:37: PM
Expert Answer:
In quadrilateral OAPB
Angle P=80
Angle A=90
Angle B=90
therfor Angle O=360-(80+90+90)=100
Now in triAngle OAB
OA=OB
therfor
Angle OAB=Angle OBA=X
X+X+100=180
X=40
therefor AngleOAB=40 degree
Answered by
| 7th Dec, 2012,
01:33: AM
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