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Asked by archita123 | 24 May, 2015, 03:24: PM
answered-by-expert Expert Answer
Let RT be the total resistance of the circuit and R' be the resistance across the parallel combination.
begin mathsize 14px style fraction numerator 1 over denominator straight R apostrophe end fraction space equals space 1 over straight R subscript 2 space plus space 1 over straight R subscript 3 space space space space space space space equals space 1 over 8 space plus space 1 over 12 space equals space fraction numerator 3 space plus space 2 over denominator 24 end fraction space equals space 5 over 24 So. space straight R apostrophe space equals space 4.8 space straight capital omega Total space resistance comma space straight R subscript straight T space equals space straight R apostrophe space plus space straight R space subscript 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 4.8 space plus space 7.2 space OR comma space straight R subscript straight T space equals space 12 space straight capital omega bold Total bold space bold Current bold space bold through bold space bold the bold space bold cirucit bold comma bold space bold I subscript bold T bold space bold colon straight I subscript straight T space equals space straight V over straight R subscript straight T space equals space 6 over 12 Or comma space straight I subscript straight T space equals space 0.5 space straight A bold Potential bold space bold Difference bold space bold across bold space bold R subscript bold 1 bold colon straight V subscript 1 space equals space straight I subscript 1 straight R subscript 1 space space space space equals space 0.5 space cross times space 7.2 straight V subscript 1 space equals space 3.6 space straight V bold Current bold space bold across bold space bold R subscript 2 bold space bold and bold space bold R subscript bold 3 bold colon The space potential space across space straight R subscript 2 space and space straight R subscript 3 space end subscript is space the space same. Thus comma space straight I subscript 2 straight R subscript 2 space equals space straight I subscript 3 straight R subscript 3 straight R subscript 2 over straight R subscript 3 space equals space straight I subscript 3 over straight I subscript 2 space straight I subscript 3 over straight I subscript 2 space equals space 8 over 12 straight I subscript 2 space end subscript equals 3 over 2 straight I subscript 3 straight I subscript straight T space equals space straight I subscript 1 space equals space straight I subscript 2 space plus space straight I subscript 3 space equals space 0.5 space straight A 0.5 space equals space 3 over 2 straight I subscript 3 space plus straight I subscript 3 straight I subscript 3 space equals space 0.2 space straight A Therefore comma space straight I subscript 2 space equals space 0.3 space straight A bold Potential bold space bold Difference bold space bold across bold space bold R subscript 2 bold space bold and bold space bold R subscript bold 3 bold colon straight V subscript 2 space equals space straight I subscript 2 straight R subscript 2 space end subscript equals space 0.3 space cross times space 8 space equals space 2.4 space straight V straight V subscript 3 space equals space straight I subscript 3 straight R subscript 3 space end subscript equals space 0.2 space cross times space 12 space equals space 2.4 space straight V end style
 
The potential drop across R1 = 3.6 V
Answered by Jyothi Nair | 24 May, 2015, 03:43: PM

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CBSE 10 - Physics
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