Asked by manoj255 | 21st Nov, 2010, 09:18: PM

Expert Answer:

let mass of the block = m
then mass of rope     = m/2
total mass of system = (m + m/2)  = 3m/2
Total (net) force on the system = 6 N
therefore acceleration of the system =
since rope is uniform , it impliies mass of half of the rope =
now consider the system A :
bock + half part of the attached
In this system the only external force acting is due to the tension of the rope.
and the acceleration we found to be equal to 4/m
the net mass of this new system  MA = m + m/4
                                                      = 5m/4
let tension force be T ( at middle of rope)
    = 5m/4  *  4/m
    = 5 N

Answered by  | 24th Nov, 2010, 11:44: AM

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