Asked by  | 17th Apr, 2012, 09:55: PM

Expert Answer:

angle ABC=60degrees (equilateral triangle)

component of velocity of B along AB =vcos60=v/2

A moves towards B with velocity 'v'

Therefore rate of decrease of the distance 'a' between A and B is=v+v/2=3v/2

time required for distance between A & B from a to zero  is =a/(3v/2)=2a/3v

Answered by  | 18th Apr, 2012, 01:30: PM

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