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$square root of fraction numerator s e c theta minus 1 over denominator s e c theta plus 1 end fraction end root plus square root of fraction numerator s e c theta plus 1 over denominator s e c theta minus 1 end fraction end root equals 2 cos e c theta$

Asked by bhattjeewanti9999 | 14 Dec, 2018, 11:12: AM

Expert Answer

begin mathsize 12px style square root of fraction numerator s e c space theta space minus 1 over denominator s e c space theta plus 1 end fraction end root space plus space square root of fraction numerator s e c space theta space plus 1 over denominator s e c space theta minus 1 end fraction end root space equals space square root of fraction numerator open parentheses s e c space theta space minus 1 close parentheses over denominator open parentheses s e c space theta plus 1 close parentheses end fraction cross times fraction numerator open parentheses s e c space theta space minus 1 close parentheses over denominator open parentheses s e c space theta space minus 1 close parentheses end fraction end root plus square root of fraction numerator open parentheses s e c space theta space plus 1 close parentheses over denominator open parentheses s e c space theta minus 1 close parentheses end fraction cross times fraction numerator open parentheses s e c space theta space plus 1 close parentheses over denominator open parentheses s e c space theta space plus 1 close parentheses end fraction end root equals space fraction numerator open parentheses s e c space theta space minus 1 close parentheses over denominator tan space theta end fraction space plus space fraction numerator open parentheses s e c space theta space plus 1 close parentheses over denominator tan space theta end fraction space equals space fraction numerator 2 space s e c space theta over denominator tan space theta end fraction space equals space 2 space cos e c space theta end style

Answered by Thiyagarajan K | 14 Dec, 2018, 12:20: PM

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