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CBSE Class 11-science Answered

Asked by Amyra B | 01 Nov, 2014, 09:21: AM
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Solution:
 
Let the initial distance between P and Q be x.
At t1 =x/2,  P receives the ball.
N e x t space b a l l space a t comma space t subscript 2 space equals space fraction numerator x space minus 5 space over denominator 2 end fraction plus space 5 T h e r e f o r e comma space capital delta t space equals space t subscript 2 space minus space t subscript 1 space equals space 5 over 2  I n space s e c o n d space c a s e comma space a t space t space equals 0 comma space P space t h r o w s space t h e space b a l l.
H e r e comma space t subscript 1 space equals space x over 3 space N e x t space b a l l space a t comma t subscript 2 space equals space fraction numerator x space minus space 5 over denominator 3 end fraction plus space 5 T h e r e f o r e comma capital delta t space equals 10 divided by 3
Thus, balls will be received by Q once every 2.5s in case I and once every 3.3s in case II.
 
Answered by Sheetal Jalan | 02 Nov, 2014, 05:08: PM
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