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CBSE Class 12-science Answered

Find space dy over dx space where space straight x equals open parentheses straight t plus 1 over straight t close parentheses comma space straight y equals 2 to the power of straight t plus 1 over straight t end exponent
Asked by Topperlearning User | 04 Aug, 2014, 09:20: AM
answered-by-expert Expert Answer

Here space dx over dt equals open parentheses 1 minus 1 over straight t squared close parentheses
dy over dt equals 2 to the power of open parentheses straight t plus 1 over straight t close parentheses end exponent log space 2 open parentheses 1 minus 1 over straight t squared close parentheses
therefore dy over dx
equals dy over dt cross times dt over dx
equals 2 to the power of open parentheses straight t plus 1 over straight t close parentheses end exponent log space 2 open parentheses 1 minus 1 over straight t squared close parentheses cross times fraction numerator 1 over denominator open parentheses 1 minus 1 over straight t squared close parentheses end fraction
equals 2 to the power of open parentheses straight t plus 1 over straight t close parentheses end exponent log space 2

Answered by | 04 Aug, 2014, 11:20: AM
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