CBSE Class 9 Answered
Asked by Shreyas Pande | 14 Feb, 2014, 04:29: PM
Expert Answer
ABC is an equilateral triangle and D, E and F are the midpoints of BC, CA and AB respectively.
Now, we have AB = BC = CA (sides of equilateral triangle are equal)
According to mid-point theorem,
DE is parallel to AB and DE = (1/2) AB
Similarly, DF is parallel to AC and DF = (1/2)AC and EF is parallel to BC and EF= (1/2)BC.
Since AB = BC = CA,
(1/2)AB = (1/2)BC = (1/2)CA
Thus, DE = EF = DF
Hence, DEF is an equilateral triangle(all the sides are equal)
Answered by | 14 Feb, 2014, 04:56: PM
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