CBSE Class 11-science Answered
*****
Asked by manoj255 | 21 Nov, 2010, 09:22: PM
Expert Answer
Dear student,
consider a weight attached to a string and whirled in a circular motion.
The force maintaining the object in its orbit is always perpendicular to the displacement of the object and thus no work is done by this force.
Note also that if an object moves at a constant velocity over a frictionless surface, no force acts on the object and thus no work is done in order to produce the displacement.
Hope this helps.
Thanking you
Regards
Team
Topperlearning.com
Answered by | 23 Nov, 2010, 01:30: PM
Concept Videos
CBSE 11-science - Physics
Asked by pranavsrinivas82 | 08 Jan, 2024, 11:30: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rame123shshiv | 14 Nov, 2023, 06:18: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kfcispuppy | 30 Sep, 2023, 10:06: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sakethrockzz007 | 14 Aug, 2023, 04:30: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sahuaryanbro1.0 | 01 Jan, 2023, 10:17: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by subhankarnanda123 | 20 Dec, 2022, 08:36: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kashyspalbert91 | 11 Mar, 2022, 04:11: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by alkrishna4652 | 24 Feb, 2022, 01:46: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shreyamishra270304 | 04 Aug, 2021, 08:32: AM
ANSWERED BY EXPERT