Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

*****
Asked by manoj255 | 21 Nov, 2010, 09:22: PM
answered-by-expert Expert Answer
Dear student,
consider a weight attached to a string and whirled in a circular motion. 

The force maintaining the object in its orbit is always perpendicular to the displacement of the object and thus no work is done by this force.

Note also that if an object moves at a constant velocity over a frictionless surface, no force acts on the object and thus no work is done in order to produce the displacement.

Hope this helps.

Thanking you

Regards

Team

Topperlearning.com

Answered by | 23 Nov, 2010, 01:30: PM
CBSE 11-science - Physics
Asked by pranavsrinivas82 | 08 Jan, 2024, 11:30: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kfcispuppy | 30 Sep, 2023, 10:06: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by subhankarnanda123 | 20 Dec, 2022, 08:36: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by divyanshkr13 | 16 Jun, 2022, 10:25: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kashyspalbert91 | 11 Mar, 2022, 04:11: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shreyamishra270304 | 04 Aug, 2021, 08:32: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×