If.......................

Asked by sonali221994 | 25th Jan, 2010, 06:12: PM

Expert Answer:

tan2A = sec2A -1

tan2A = (x+1/4x)2 -1

= x2 + 1/2 + 1/16x2 - 1

= x2 - 1/2 + 1/16x2

= (x - 1/4x)2

tanA = ±(x - 1/4x)

Hence,

secA + tanA = (x+1/4x) ± (x+1/4x)

= 2x or 1/2x

Regards,

Team,

TopperLearning.

Answered by  | 25th Jan, 2010, 06:26: PM

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