If.......................
Asked by sonali221994 | 25th Jan, 2010, 06:12: PM
Expert Answer:
tan2A = sec2A -1
tan2A = (x+1/4x)2 -1
= x2 + 1/2 + 1/16x2 - 1
= x2 - 1/2 + 1/16x2
= (x - 1/4x)2
tanA = ±(x - 1/4x)
Hence,
secA + tanA = (x+1/4x) ± (x+1/4x)
= 2x or 1/2x
Regards,
Team,
TopperLearning.
Answered by | 25th Jan, 2010, 06:26: PM
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