If begin mathsize 12px style f open parentheses x close parentheses equals fraction numerator 1 minus x over denominator 1 plus x end fraction space t h e space d o m a i n space o f space f to the power of negative 1 end exponent open parentheses x close parentheses space space i s
space i. R space space space space space space space i i. R minus open curly brackets negative 1 close curly brackets space space space space space i i i. open parentheses negative infinity comma negative 1 close parentheses space space space space space space space i v. space open parentheses negative 1 comma infinity close parentheses end style

Asked by sunil2791 | 24th Jun, 2017, 03:20: PM

Expert Answer:

begin mathsize 16px style straight f left parenthesis straight x )= fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction
Find space inverse space of space the space function
straight y equals fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction
straight y open parentheses 1 plus straight x close parentheses equals 1 minus straight x
straight y plus xy equals 1 minus straight x
straight x plus xy equals 1 minus straight y
straight x equals fraction numerator 1 minus straight y over denominator 1 plus straight y end fraction
rightwards double arrow straight y equals fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction
Hence comma space straight x not equal to negative 1
Domain space is space straight R equals open curly brackets negative 1 close curly brackets end style

Answered by Sneha shidid | 26th Jun, 2017, 01:15: PM