if y=x^x+(sin)^x,find dy/dx

Asked by saravanan.k | 28th Jul, 2011, 11:47: PM

Expert Answer:

y=x2 +(sinx)
Taking log both sides
=>logy=2logx+xlog(sinx)
=>1/y(dy/dx)=(2/x)+x.(1/sinx).cosx+log(sinx)
=>dy/dx=y[(2/x)+x.cotx+log(sinx)]
 

Answered by  | 29th Jul, 2011, 01:53: AM

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