CBSE Class 9 Answered
if xsquare+1/xsquare=83, then find xcube-1/xcube?
Asked by kartikeya vimal | 17 Jun, 2013, 06:10: PM
Expert Answer
x2 + 1/x2 = 83
x2 + 1/x2 - 2 = 83 - 2
(x - 1/x)2 = 81
(x - 1/x)2 = 92
x - 1/x = +/- 9
Now,
(x - 1/x)3 = +/- 93
x3 - 1/x3 - 3*x*1/x (x - 1/x) = +/- 729
Now, substituting the value of x - 1/x, we get,
x3 - 1/x3 - 3*9 = 729 and x3 - 1/x3 + 3*9 = -729
x3 - 1/x3 - 27 = 729 and x3 - 1/x3 + 27 = -729
x3 - 1/x3 = 756 and x3 - 1/x3 = -756
Answered by | 17 Jun, 2013, 10:01: PM
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