CBSE Class 12-science Answered
If x= 2t/1+t^2 ,y=1-t^2/1+t^2 then Dy/DX +x/y is
(A) 1
(B) 2
(C) 0
(D)4t^2
Asked by sd151299 | 27 Oct, 2019, 06:23: PM
Expert Answer
x = 2t/1 + t2 and y = (1 - t2)/(1 + t2)
Let t = tan θ
x = 2tan θ/(1 + tan2 θ) and y = (1 - tan2 θ)/(1 + tan2 θ)
x = sin 2θ and y = cos 2θ
dx/dθ = 2cos 2θ and dy/dθ = -2sin 2θ
dy/dx = -2sin 2θ/2cos 2θ
dy/dx = -x/y
dy/dx + x/y = 0
Answered by Sneha shidid | 30 Oct, 2019, 09:33: AM
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