if x^2-ax+2a+5=0 is a perfect square,then find the value/s of a.

Given, x²-ax+2a+5 is a perfect square. So, it will be of the form (x - t)², where t is a constant.

x²-ax+2a+5 = (x - t)²

x²-ax+2a+5 = x² - 2xt + t²

Comparing both sides, we get,

-ax = -2xt 

So, a = 2t

Also, 2a+5 = t²

4t + 5 =  t²

 t² - 4t - 5 = 0

(t + 1) (t - 5) = 0

t = -1 or 5

So, a = -2 or 10