IF,x=1/7+4ROOT3 AND Y=1/7-4ROOT3 FIND THE VALUE OF 5XSQUARE-7XY-5YSQUARE

Asked by Aditya kumar | 2nd Jun, 2013, 03:04: PM

Expert Answer:

5X^2=5(1/7+4)^2
       =5(7-4)^2
7XY=7(1/7+4)(1/7-4)
     =7(1/49-48)=7
5Y^2=5(1/7-4)^2
       =5(7+4)^2
5X^2-7XY-5Y^2=-7(1+80)
this is the correct answer

Answered by  | 2nd Jun, 2013, 03:41: PM

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