If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J,  then what is the electric potential at this point? 

Asked by pdcavita | 26th Nov, 2017, 08:52: PM

Expert Answer:

Work-done = P.D. / charge
 
P.D. =15 x 20 x 10-3  = 300x10-3  volts

Answered by Gajendra | 27th Nov, 2017, 11:43: AM

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