If two zeroes of the polynomial p(x) = x^4 - 6x^3 - 26x^2 + 138x - 35 are 2 + root 3 and 2 - root 3, find the other zeroes.
Asked by | 9th Sep, 2012, 08:51: PM
given that (x - 2 - root 3) and (x - 2 + root 3) are factors. this means x^2 - 4x + 1 is a factor of p(x).
now divide p(x) by the above polynomial which is its factor.
thereafter, find the zeroes of the obtained quotient.
the zeroes of the quotient will be the remaining two zeroes of p(x).
Answered by | 9th Sep, 2012, 11:32: PM
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