if there are 3 bowls and 7 toys.what is the number of ways of putting the toys in the bowls such that each bowl must have atleast 1 toy?

Any three toys can be arranged in 3 bowls in 3! = 6 ways,

Now remaining 4 toys where a bowl can hold any number of toys.

So number of ways of putting those 4 toys in 3 bowls is 3⁴ = 81.

Total number of ways = 6x81 = 486

Regards,

Team,

TopperLearning.