if there are 3 bowls and 7 toys.what is the number of ways of putting the toys in the bowls such that each bowl must have atleast 1 toy?

Asked by adityalearn28 | 24th Jul, 2010, 12:00: AM

Expert Answer:

Any three toys can be arranged in 3 bowls in 3! = 6 ways,
Now remaining 4 toys where a bowl can hold any number of toys.
So number of ways of putting those 4 toys in 3 bowls is 34 = 81.
Total number of ways = 6x81 = 486
Regards,
Team,
TopperLearning.

Answered by  | 26th Jul, 2010, 09:45: AM

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