if thepolynomial 2x3+ax2+3x-5 and x3+x2-2x+a leave the same remainder when divided by (x-2) ,find the value of a.
Asked by deepa1973 | 13th Jun, 2015, 08:11: AM
By remainder theorem, the remainder when f(x)=2x3+ax2+3x-5 is divided by (x-2) is equal to f(2).
Similarly, the remainder when g(x)=x3+x2-2x+a is divided by (x-2) is equal to g(2).
Since, both the polynomial leave the same remainder, we get
=> 2X23 + aX22 + 3X2 - 5 = 23 + 22 - 2X2 + a
Answered by satyajit samal | 14th Jun, 2015, 08:44: AM
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