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If the two slits in Young's double slit experiment have width ratio 4:1, deduce the ratio of the intensity of maxima and minima in the interference pattern?

PLEASE EXPLAIN THE ANSWER

Asked by modi72879 | 14th Oct, 2017, 01:18: PM

Expert Answer:

$begin mathsize 12px style Width space is space directly space proportional space to space the space intensity And space intensity space is space directly space proportional space to space square space of space amplitude Maximum space Intensity space the space square space of space sum space of space both space amplitude space space and space minimum space intensity space will space be space square space of space the space subtraction space of space both space amplitude. straight w subscript 1 over straight w subscript 2 equals straight I subscript 1 over straight I subscript 2 equals straight A squared over straight B squared 4 over 1 equals straight A squared over straight B squared straight A over straight B equals 2 over 1 semicolon space straight A equals 2 xB straight I subscript max over straight I subscript mini equals fraction numerator left parenthesis straight A plus straight B right parenthesis squared over denominator left parenthesis straight A minus straight B right parenthesis squared end fraction equals fraction numerator left parenthesis 2 straight B plus straight B right parenthesis squared over denominator left parenthesis 2 straight B minus straight B right parenthesis squared end fraction equals open parentheses fraction numerator begin display style 3 straight B end style over denominator begin display style straight B end style end fraction close parentheses squared equals 9 over 1 end style$

Answered by Gajendra | 4th Dec, 2017, 11:24: AM

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