If the two slits in Young's double slit experiment have width ratio 4:1, deduce the ratio of the intensity of maxima and minima in the interference pattern?
PLEASE EXPLAIN THE ANSWER
Asked by modi72879
| 14th Oct, 2017,
01:18: PM
Expert Answer:
Answered by Gajendra
| 4th Dec, 2017,
11:24: AM
Concept Videos
- coherent sources
- two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
- We for equal wave intensities the intensity at a point is given by
but where does the formula
come from??
- Question 15
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- In young double slit experiment, slit with ratio is 3:2 then find out the ratio of the maximum and minimum intensity of interference of light.
- How is phase difference related to path difference?
- In Young's double slit experiment, the distance between the slit is kept smaller than the wavelength of the light. What is the effect?
- Why is Interference pattern not detected when the two coherent sources are far apart?
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