If the temperature of a uniform rod is slightly increased by ?t, its moment of inertia I about a line parallel to itself will increase by what?

Asked by JAYACHANDRAN B | 4th Feb, 2012, 09:49: AM

Expert Answer:

The moment of inertia of a rod about a perpendicular bisector is ML^2 / 12.

Change in M.I. is d(ML^2 / 12) = ML dL / 6

dL = aL dt

dI = aL dt ML / 6 = 2a(ML^2/12) dt = 2aIdt

Answered by  | 4th Feb, 2012, 12:25: PM

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