If the surface tension of water is 7.3×10‐²N/m then what is the excess pressure inside a spherical drop of water of radius 0.1 m?

Asked by banerjee2000 | 11th Apr, 2022, 11:10: AM

Expert Answer:

TO find: Express pressure
Express space pressure equals fraction numerator 2 straight T over denominator straight R end fraction comma space where space straight T space is space tension space and space straight R space is space radius
Express space pressure equals fraction numerator 2 cross times 7.3 cross times 10 to the power of negative 2 end exponent over denominator 10 to the power of negative 1 end exponent end fraction equals 1.46 space straight N divided by straight m squared

Answered by Renu Varma | 11th Apr, 2022, 11:23: AM