CBSE Class 10 Answered
if the roots of the equation (b-c)xsquare+(c-a)x+(a-b)=0 are equal, then show that a,b,c are in AP.
Asked by riyaliz | 22 Jul, 2008, 10:17: PM
Expert Answer
if the roots are equal , then discriminant b^2 - 4ac = 0
( c- a) ^2 - 4 ( b-c ) ( a-b) = 0
c^2 + a^2 - 2 ac - 4 [ ba-b^2 -ca +bc] = 0
c^ 2 + a^2 + 2ac + 4b^2 -4ab - 4bc = 0
[ c + a] ^2 = 4b [ a +c -b ]
if a, b,c are in A.P then c+a = 2b
substituting this c+a = 2b in the above equation , we will get [ c+a] ^2 = 4b[a+c -b] becomes
[ 2b ]^2 = 4b[ 2b - b] = 4b [ b] = 4b^2 THE CONDITION SATISFIES.
therefore a, b,c are in A.P
Answered by | 23 Jul, 2008, 06:24: PM
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