if the radius of earth shrinks by 2% , mass remaining the same, then how would the value of acceleration due to gravity change???
Asked by toppin | 4th Nov, 2010, 04:48: PM
The acceleration due to gravity at the surface of earth is g = G m / R2 .
The radius of eath decreases by 2 %, therefore
R' = R - 0.02 R = 0.98R.
Now acceleration due to gravity will be :
g' = GM / ( 0.98 R )2 = 1.04 g
Percentage increase in acceleration due to gravity
[(g' - g )/g ] x 100 = 4 %
We hope this clarifies your doubt.
Answered by | 6th Nov, 2010, 03:47: PM
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