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If the point p(x,y) is equidistant from the pts A(5,1)and B(-1,5)p.t x=y
Asked by | 17 Jan, 2012, 09:39: AM
Distance of p from A = ?(x-5)2+(y-1)2

Distance of p from B = ?(x+1)2+(y-5)2

Now distance from A = distance from B

?(x-5)2+(y-1)2 =?(x+1)2+(y-5)2

squaring both sides

(x-5)2+(y-1)2 =(x+1)2+(y-5)2

rearranging terms we get

(x-5)2 -(x+1)2 =(y-5)2 -(y-1)2

(x-5-x-1)(x-5+x+1)=(y-5-y+1)(y-5+y-1)

-6(2x-4)=-4(2y-6)

Hence -12x=-8y

or, 3x=2y not x=y as you have posted a wrong question

thank you
Answered by | 17 Jan, 2012, 03:03: PM

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