CBSE Class 10 Answered
If the point p(x,y) is equidistant from the pts A(5,1)and B(-1,5)p.t x=y
Asked by | 17 Jan, 2012, 09:39: AM
Expert Answer
Distance of p from A = ?(x-5)2+(y-1)2
Distance of p from B = ?(x+1)2+(y-5)2
Now distance from A = distance from B
?(x-5)2+(y-1)2 =?(x+1)2+(y-5)2
squaring both sides
(x-5)2+(y-1)2 =(x+1)2+(y-5)2
rearranging terms we get
(x-5)2 -(x+1)2 =(y-5)2 -(y-1)2
(x-5-x-1)(x-5+x+1)=(y-5-y+1)(y-5+y-1)
-6(2x-4)=-4(2y-6)
Hence -12x=-8y
or, 3x=2y not x=y as you have posted a wrong question
thank you
Answered by | 17 Jan, 2012, 03:03: PM
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