if the perimeter of a semi-circular protractor is 72cm then the diameter of the protractor ?

Asked by shouvik dutta | 29th Dec, 2013, 09:13: PM

Expert Answer:

Perimeter of semicircular protractor = 72 cm
This gives
∏r + 2r = 72
r(∏ + 2) = 72
r(22 + 14)/7 = 72
r(36)/7 = 72
r = 72 x 7 / 36
r = 14 cm

Answered by  | 29th Dec, 2013, 09:42: PM

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