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ICSE Class 10 Answered

If the line (3x-8y+5) + lambda (5x-3y+10) = 0 is parallel to the x axis, then what is the value of lambda? give steps ...
Asked by keshavendu35 | 23 Sep, 2018, 08:36: PM
Expert Answer
 
(3x-8y+5) + λ(5x-3y+10) = 0
x(3 + 5λ) + y(-8 - 3λ) + (5 + 10λ) = 0
 
As we know, equation of x-axis, y = 0.
 
Since, two llines are parallel, slope of x - axis is equal to slope of the given line.
 
Slope of x - axis is zero.  (since, y = 0)
 
begin mathsize 16px style Slope space space equals space fraction numerator negative straight a over denominator straight b end fraction end style 
In x(3 + 5λ) + y(-8 - 3λ) + (5 + 10λ) = 0, 
 
begin mathsize 16px style Slope space space equals space fraction numerator negative straight a over denominator straight b end fraction space equals space fraction numerator negative left parenthesis 3 space plus space 5 lambda right parenthesis over denominator left parenthesis negative 8 minus 3 lambda right parenthesis end fraction space equals space 0 rightwards double arrow space minus 3 space minus space 5 lambda space equals space 0 rightwards double arrow lambda space equals space fraction numerator negative 3 over denominator 5 end fraction end style

Answered by Yasmeen Khan | 24 Sep, 2018, 10:37: AM

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