If the first and the nth term of aG.P are a and b, and P is the product of first n terms, prove :

Asked by  | 6th Jul, 2008, 11:35: PM

Expert Answer:

it is as we have inserted (n-2) G.M. between a and b.

r= (b/a)(n-2+1)= (b/a)(n-1)

so product of all these terms P= a.ar.ar2.ar3........ar(n-1)



put the value of r

P= an . (b/a)n/2 = (ab)n/2

i.e. P2=(ab)n.

Answered by  | 10th Aug, 2008, 05:16: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.