If the coordinates of the points P and Q are (4,3) and (-1,7). Then find the abscissa of a point R on the line segment PQ such that PR/PQ=3/5

Asked by  | 17th Dec, 2012, 09:25: PM

Expert Answer:

PR/PQ = 3/5

Let PR = 3x and PQ = 5x

therefore, PR : PQ = 3 : 5

now coordinates of R will be ( x1m2 + x2m1 / m1 + m2 , y1m2 + y2m1 / m1 + m2 )

(where x1 = 4 , x2 = -1 , y1 = -3 , y2 = 7 , m1 = 3 and m2 = 5 )

so coordinates of R become ( 4*5 + ( -1)3 / 3 + 5 , ( -3) 5 + 7*3 / 3 + 5 )

i.e., ( 20 - 3 / 8 , -15 + 21 / 8 )

= ( 17/8 , 3/4 )

therefore, abscissa of point R will b 3/4....

Answered by  | 18th Dec, 2012, 10:25: AM

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