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If the bisectors of B and C of triangle of a ABC intersect at O, then prove that BOC = 90o + . Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM Expert Answer

In ABC A + B + C =180o    (angle sum of a ) OBC + BCO + BOC =180o    (angle sum of BOC)
But OBC =  B and BCO =  C   B +  C + BOC =180o  ( B + C + A) + BOC = 180o +  A         (adding  A to both sides)  (180o) + BOC = 180o +  A 90o + BOC = 180o +  A  BOC = 90o +  A
Hence proved.
Answered by | 04 Jun, 2014, 03:23: PM

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