If the bisectors of B and C of triangle of a ABC intersect at O, then prove that BOC = 90o + .



Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

In ABC A + B + C =180o    (angle sum of a )

OBC + BCO + BOC =180o    (angle sum of BOC)
But OBC = B and BCO = C
B +C + BOC =180o
(B + C + A) +BOC = 180o + A         (adding A to both sides)
(180o) + BOC = 180o + A
 90o + BOC = 180o + A
BOC = 90o +A
Hence proved.

Answered by  | 4th Jun, 2014, 03:23: PM