If the binding energy of the electron in hydrogen atom is 13.6 eV,  calculate the energy required to remove the electron from the first excited state of Li++ .

 

Asked by Charvi Ahuja | 11th Apr, 2014, 12:29: AM

Expert Answer:

E subscript n equals minus 13.6 space open parentheses Z over n close parentheses squared e V F o r space t h e space f i r s t space e x c i t e d space s t a t e comma space n space equals space 2 space a n d space f o r space L i to the power of plus plus end exponent comma space z space equals space 3 E subscript 2 space equals space minus 13.6 space x space open parentheses 3 over 2 close parentheses squared equals minus 30.6 space e V. T h u s space t h e space i o n o z a t i o n space e n e r g y space f o r space t h e space e x c i t e d space s t a t e space o f space L i to the power of plus plus end exponent space i s space 30.6 space e V.

Answered by  | 11th Apr, 2014, 12:50: AM

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