If PSQ is the focal chord of the parabola y^2=8x such that SP=6 then the length of SQ is
1)3
2)4
3)24
Asked by dineshchem108
| 21st Oct, 2018,
07:54: PM
Expert Answer:
The coordinates of a focal chord of a parabola are P(at2 , 2at) and Q 
y2 = 8x
comparing with y2 = 4ax we get a = 2
Hence, coordinates of a focus is (2, 0)
SP = 6
SP2 = 36
(2 - 2t2)2 + (4t)2 = 36
Solving it we get
t4 + 2t2 - 8 = 0
t2 = 2
Find SQ we get SQ = 3
Answered by Sneha shidid
| 22nd Oct, 2018,
05:39: PM
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