if one root of the equation 3xsquare+11x+k=0 be the reciprocal of the other,find the value of k?

Asked by riyaliz | 1st Jul, 2008, 08:51: PM

Expert Answer:

3x2+11x+k=0

x2+11/3x+k/3=0

Let the first root is =y

then 2nd root will be = 1/y

as we know product of roots is = c/a

so y * 1/y = k/3

1 = k/3

k = 3

Answered by  | 2nd Jul, 2008, 02:05: PM

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