IF ONE ROOT OF POLYNOMIAL 5X^2+13X+K IS RECIPROCAL OF THE OTHER,THENTHE VALUE OF K IS...??
Asked by | 29th May, 2012, 08:40: AM
Use the quadratic equation to get the 2 roots.
(-13 + sqrt(169-20k))/10 = 10/(-13 - sqrt(169-20k))
(-13 + sqrt(169-20k))*(-13 - sqrt(169-20k)) = 100
169 - (169-20k) = 100
20k = 100
k = 5
Use the quadratic equation to get the 2 roots.
(-13 + sqrt(169-20k))/10 = 10/(-13 - sqrt(169-20k))
(-13 + sqrt(169-20k))*(-13 - sqrt(169-20k)) = 100
169 - (169-20k) = 100
20k = 100
k = 5
Answered by | 29th May, 2012, 08:56: AM
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