If one of the zeroes of quadratic polynomial (x-1)x*x+kx+1 is -3,then what is the value of k?

Asked by shananoureen | 10th May, 2013, 07:58: PM

Expert Answer:

Since, -3 is a root for f(x) = (x-1)x*x+kx+1
Hence, f(-3) = 0
(-3-1)*(-3)*(-3) + k(-3) +1 =0
-4*9 -3k +1 = 0
-36-3k+1 = 0
3k = -35
k = -35/3

Answered by  | 11th May, 2013, 02:20: AM

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