If LtanA +MsecA = N and L' tanA - M' secA = N' prove the following:

Asked by harshgupta | 30th Nov, 2008, 07:38: PM

Expert Answer:

LtanA +MsecA = N.....(1)

L' tanA - M' secA = N'.(2)

solve for tanA & secA  we get tana(ML' +M'L) = (NM' + MN')  & secA(ML' +M'L) =(NL' -LN')

we know that tan2A + 1   = sec2A put the value and get the answer

Answered by  | 16th Dec, 2008, 07:37: PM

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