if (k-3),(2k+1) and (4k+3) are three consecutive terms of an arthmetic progression,find the value of k

Asked by t.singireddy | 10th Nov, 2019, 03:21: PM

Expert Answer:

(k-3),(2k+1) and (4k+3) are three consecutive terms of an arithmetic progression.

Hence,

(2k + 1) - (k - 3) = (4k + 3) - (2k + 1)

k + 4 = 2k + 2

k = 2

 

Answered by Renu Varma | 10th Nov, 2019, 07:50: PM