CBSE Class 11-science Answered
If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 10 kg of this gas
Asked by Anil | 16 May, 2017, 03:36: PM
Expert Answer
If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 10 kg of this gas:
Isobutane and n-Butane have same chemical formula (C4H10) and give same combustion reaction.
2C4H10+13O2→8CO2+10H2O
This means 2 moles of this mixture requires 13 moles of oxygen.
Molecular mass of butane=58g/mol
Molecular mass of oxygen=32g/mol
Thus, 116 g mixture needs 13 x 32 g = 416 g oxygen
10 kg of the mixture = 10 x 103 g needs = 416 x 10 x 103 / 116 = 35862.06 g of oxygen
Therefore, 35.862 kg oxygen is used.
Answered by Prachi Sawant | 16 May, 2017, 04:53: PM
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