If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 10 kg of this gas

Asked by Anil | 16th May, 2017, 03:36: PM

Expert Answer:

If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 10 kg of this gas:
 
Isobutane and n-Butane have same chemical formula (C4H10) and give same combustion reaction.
 
2C4H10+13O28CO2+10H2O
 

This means 2 moles of this mixture requires 13 moles of oxygen.

Molecular mass of butane=58g/mol

Molecular mass of oxygen=32g/mol

Thus, 116 g mixture needs 13 x 32 g = 416 g oxygen

10 kg  of the mixture  = 10 x 103 g needs = 416 x 10 x 103 / 116 = 35862.06 g of oxygen

Therefore, 35.862 kg oxygen is used.



Answered by Prachi Sawant | 16th May, 2017, 04:53: PM