if in a question to verify law of multiple proportions
for eg
CO2 and CO
in case of carbn dioxide % of oxygen is 72.7% and of carbon 27.3%
in case of carbon monoxide % of oxygen is 57.14% and carbonis 42.8%
in this case in order to verify law of definite proportions i multiply percentages in each case to molecular masses of their respective compounds for eg.
72.7/100*44=32 and 27.3 /100*44=12
and 57.14/100*28=16 and 42.8 /100* 28 =12 so 32:16 =2:1
Asked by Viswanath | 27th Apr, 2014, 05:24: PM
Dear Viswanath,
The calculation that you have shown to verify the law of multiple proportion is correct.
Regards
Topperlearning Team.
Regards
Topperlearning Team.
Answered by Prachi Sawant | 8th May, 2014, 11:24: AM
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