If I have given cyclotron applied voltage as 20kilo volt. A proton rotates and after 50 cycles it goes out....Find the energy of particle.
Asked by lekhram2410 | 26th Mar, 2020, 08:14: AM
In cyclotron, proton is accelerated twice in each cycle .
Gain in kinetic energy Δk per cycle = 2 × q × V
where q is charge on proton and V is accelerating potential difference
Gain in kinetic energy Δk per cycle = 2 × 1.602 × 10-19 × 20000 = 6.4 × 10-15 J
Gain in kinetic energy Δk after 50 cycle = 6.4 × 50 × 10-15 J = 3.2 × 10-13 J
Answered by Thiyagarajan K | 26th Mar, 2020, 09:38: AM
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