If I have given cyclotron applied voltage as 20kilo volt. A proton rotates and after 50 cycles it goes out....Find the energy of particle.

Asked by lekhram2410 | 26th Mar, 2020, 08:14: AM

Expert Answer:

In cyclotron, proton is accelerated twice in each cycle .
 
Gain in kinetic energy Δk per cycle = 2 × q × V
where q is charge on proton and V is accelerating potential difference

Gain in kinetic energy Δk per cycle = 2 × 1.602 × 10-19 × 20000 = 6.4 × 10-15 J
 
Gain in kinetic energy Δk after 50 cycle  = 6.4 × 50 × 10-15 J = 3.2 × 10-13 J

Answered by Thiyagarajan K | 26th Mar, 2020, 09:38: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.