if hydrogen atom is excited by giving 8.4eV energy then number of emitted spectral lines wil be?

Asked by shaikh sameer | 15th Oct, 2013, 10:20: AM

Expert Answer:

   E µ 1/n2

 For n=1, E = 13.6 eV

Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to ¥

For n=2, E = 13.6(1 - (1 / 22) = 10.2

This is the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed should always be between 10.2 and 13.6 eV

Hence , no emission takes place when  hydrogen atom is excited by giving 8.4eV.

Answered by Vaibhav Chavan | 15th Oct, 2013, 11:40: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.