CBSE Class 12-science Answered
if hydrogen atom is excited by giving 8.4eV energy then number of emitted spectral lines wil be?
Asked by shaikh sameer | 15 Oct, 2013, 10:20: AM
Expert Answer
E µ 1/n2
For n=1, E = 13.6 eV
Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to ¥
For n=2, E = 13.6(1 - (1 / 22) = 10.2
This is the lowest energy state possible for emission of spectral lines.
Thus the energy absorbed should always be between 10.2 and 13.6 eV
Hence , no emission takes place when hydrogen atom is excited by giving 8.4eV.
Answered by Vaibhav Chavan | 15 Oct, 2013, 11:40: AM
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