If element with principal quantum number n>4 were not allowed in nature, then the number of possible elements would be

Asked by samairakhanna185 | 20th Mar, 2019, 10:18: PM

Expert Answer:

N=1 present K-shell and the number of elements having K shell=2 N=2 present L shell and the number of element having L shell=8 N=3 present N shell and the number of elements having N shell = 18 N=4 present N shell and the number of elements having N shell = 32 Total number = 2+8+18+32=60

Answered by Ankit K | 21st Mar, 2019, 09:09: AM

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