If d is the H.C.F of 45 and 27, find x and y satisfying d=27x +45y ..?? urgent.!!
Asked by Ritwika Sharma | 1st Sep, 2012, 07:19: PM
Expert Answer:
HCF of 45 and 27 is 9 (by division lemma)
therefore 27x+45y=9
let x be 2
27(2)+45y=9
54+45y=9
45y=9-54
y=-45/45
y=-1
therefore x=2 y=-1
HCF of 45 and 27 is 9 (by division lemma)
therefore 27x+45y=9
let x be 2
27(2)+45y=9
54+45y=9
45y=9-54
y=-45/45
y=-1
therefore x=2 y=-1
Answered by | 2nd Sep, 2012, 10:42: AM
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