If ax^2+bx+c has no real roots then?

a(a+b+c)>0

(a+b+c)>0

b(a+b+c)>0

Asked by aahnik.mohanty | 19th Jun, 2019, 09:05: PM

Expert Answer:

ax2+bx+c =0
does not have real roots hence its graph will be above x axis or below x axis
 
for a>0
f(1)>0
a+b+c>0
so,
a(a+b+c)>0
 
for a<0
f(1)<0
a+b+c<0
so,
a(a+b+c)>0
 
so, ans is a(a+b+c)>0

Answered by Arun | 20th Jun, 2019, 09:45: AM