IF tan ϕ equals fraction numerator n space sin theta over denominator 1 minus n space cos theta end fraction and tan theta equals fraction numerator y space sin ϕ over denominator 1 minus y space cos ϕ end fractionthen prove that (y sinϕ)+(n costheta)=1

Asked by abinash.gupta003 | 28th Jul, 2017, 02:46: PM

Expert Answer:

begin mathsize 16px style tanϕ equals fraction numerator nsinθ over denominator 1 minus ncosθ end fraction
If space you space solve space this space you space will space get space
sinϕ equals nsin open parentheses straight theta plus straight ϕ close parentheses... left parenthesis straight i right parenthesis
and space solving space tanθ equals fraction numerator nsinϕ over denominator 1 minus ncosθϕ end fraction
sinθ equals ysin open parentheses straight theta plus straight ϕ close parentheses..... left parenthesis ii right parenthesis
from space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis
ysinϕ equals nsinθ
Using space this space you space can space prove space it.

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Answered by Sneha shidid | 31st Jul, 2017, 10:12: AM